Question

Q1.A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 13 cm, find its breadth. Which shape encloses more area?​

Answer 1

Answer:

Step-by-step explanation:

Let a be the side of a square, l be the length and b be the breadth of rectangle.

As length of wire is constant, perimeter of both shapes would be same,

⇒4a=2(l+b)

⇒40=2(12+b)

⇒b=18 cm

Area of square=a  

2

=10  

2

=100cm  

2

 

Area of rectangle=lb=12×18=216cm  

2

 

⇒ Area of rectangle is greater by 116cm  

2

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Answer 2

Step-by-step explanation:

area of a square=area of rectangle

side x side = (length x breadth)

(10 x 10 )cm =(13 x. breadth)cm

100cm² = (13 x breadth)cm

100cm²÷13cm = breadth

7.69 cm =breadth

or

breadth=7.69

area of rectangle = (length ×breadth)

13×7.69=99.97

square enclosed more area