In Fig. 8.129, PQ++RS, ∠AEF =95°, ∠BHS =110° and ∠ABC =x°. Then the value of x is,
A. 15°
B. 25°
C. 70°
D. 35°
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The correct option is B. 25°
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Given : From Fig. 8.129, PQ || RS, ∠AEF = 95°, ∠BHS = 110° and ∠ABC = x°.
To find : Then the value of x.
Solution :
∠AEF = ∠AGH = 95° (Corresponding angles)
∠AGH + ∠HGB = 180° (Linear pair)
95° + ∠HGB = 180°
∠HGB = 180° - 95°
∠HGB = 85°
∠BHS + ∠BHG = 180° (Linear pair)
110° + ∠BHG = 180°
∠BHG = 180° - 110°
∠BHG = 70°
In ∆BHG,
∠BHG + ∠HGB + ∠GBH = 180°
[By angle sum property]
70° + 85° + ∠GBH = 180°
155° + ∠GBH = 180°
∠GBH = 180° - 155°
∠GBH = 25°
Now,
∠ABC = ∠GBH = 25°
∠ABC = x° = 25°.
Hence, the value of x is 25°.
Option (B) 25° is correct.
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