In Fig. 8.137, if AB|| HF and DE||FG, then the measure of ∠FDE is
A. 108°
B. 80°
C. 100°
D. 90°
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Given : AB || HF and DE || FG
From figure it is given that :
∠HFC = 28° , ∠A = 25° and ∠BDE = 72°
AB ‖ HF and CD is a transversal.
∠HFC = ∠FDA (Corresponding angle)
∠FDA = 28°
∠FDA + ∠FDE + ∠EDB = 180° [Linear pair]
28° + ∠FDE + 72° = 180°
100° + ∠FDE = 180°
∠FDE = 180° - 100°
∠FDE = 80°
Hence , the measure of ∠FDE is 80° .
Among the given options option (B) 80° is correct.
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Answer:
hfg+fde+edb =180
28+72+fde =180
100+fde =180
fde=100-180
fde =80
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