In Fig. 8.136, if CP || DQ, then the measure of x is
A. 130°
B. 105°
C. 175°
D. 125°
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Given : CP || BQ
From figure :
∠B = 105° , ∠A = 25° and ∠PCA = x°
Produce PC to E So, PE ‖ BQ and AB is transversal.
∠QBE = ∠CEA = 105° [Corresponding angles]
In ∆ECA ,
By angle sum property :
∠CEA + ∠ECA + ∠EAC = 180°
105° + ∠ECA + 25° = 180°
130° + ∠ECA = 180°
∠ECA = 180° - 130°
∠ECA = 50°
∠PCA + ∠ECA = 180° [Linear pair]
x + 50° = 180°
x = 180° - 50°
x = 130°
Hence , the measure of x is 130° .
Option (A) 130° is correct.
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the answer is 130
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