In Fig. 8.33, find x. Further find ∠BOC, ∠COD and ∠AOD.
Attachments:
Answers
Answered by
8
I hope that you will understand it
Attachments:
Answered by
8
To find : ∠BOC, ∠COD and ∠AOD.
From figure, it is that Given: ∠AOD = (x + 10)° , ∠COD = x° and ∠BOC = (x + 20)°
∠AOD and ∠BOD form a linear pair angles :
Therefore, ∠AOD + ∠BOD = 180°
Also, ∠AOD + ∠BOC + ∠COD = 180°
( x + 10 ) + x + ( x + 20 ) = 180
3x + 30° = 180°
3x = 180° – 30°
3x = 150°
x = 150°/3
x = 50°
Now,
∠AOD = (x + 10) = 50 + 10 = 60°
∠COD = x = 50°
∠BOC = (x + 20) = 50° + 20° = 70°
Hence, ∠AOD = 60° , ∠COD = 50° and ∠BOC = 70°.
HOPE THIS ANSWER WILL HELP YOU…..
Similar questions :
In Fig. 8.34, rays OA, OB, OC, OD and OE have the common endpoint, O. Show, that ∠AOB +∠BOC +∠COD +∠DOE + ∠EOA = 360°.
https://brainly.in/question/15905564
In Fig. 8.35, ∠AOC and ∠BOC form a linear pair. If a -2b = 30°, find a and b.
https://brainly.in/question/15905566
Similar questions