In fig 8,ABCD is a rhombus whose diagonals AC and BD intersect at O.if angle OAB:angle OBA=3:2,find the measure of all the angles of COD(iss ka answer hai 36,54,90 plz pura nikna muje copy per Nikla hai )
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3x +2x=90
5x= 90
X = 18 degree
therefore angle ocd=54 ,odc=36
5x= 90
X = 18 degree
therefore angle ocd=54 ,odc=36
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ANSWER :-
angle COD = 90°
angle ODC = 36°
angle DCO = 54 °
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