Question

in fig.9.29 ar(drc) = ar(dpc) and ar(bdp) = ar(arc). show that both the quadrilaterals abcd and dcpr are trapeziums.

Answer 1

In quadrilateral Drpc triangle ar.drc is =ar.Dpc and they stand on the same base so they are between same parallel lines..therefore
dc ip parallel to rp. thats why Dcpr is trapezium..
similarly in fig.Abcd AB is parallel to dc therefore It is also a trapezium.