Question

In Fig. 9, is shown a sector OAP of a circle with centre O, containing ∠ϴ. AB is perpendicular the radius OA and meets OP produced at B. Prove that the perimeter of the shaded region is r [ tan theta + sec theta + π theta/180 - 1 ]

Answer 1

Answer:

Step-by-step explanation:

Tan@=ab/oa

Ab = rtan@

Sec@ = ob/oa

Ob = rsec@

Now circumference of scetor

@/360 ×2×22/7×r

=@ × pie× r/180

So

Perimeter of shade region

=rtan@ + rsec@ + pie@/180 -r

=r[tan@ + sec@ + pie@/180-1]

hence proved

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Answer 2

Answer:

Step-by-step explanation: