Question

Solve 9 x square - 3 bracket a square + b square bracket close X + a square b square is equal to zero

Answer 1

Answer:

Hi ,

9x² - 6ax + ( a² - b² ) = 0

9x²-3(a + b )x -3( a - b )x + (a² - b²)= 0

3x[3x - (a + b)] -(a - b )[3x - ( a + b )]= 0

[ 3x -( a + b ) ][ 3x - ( a - b ) ] = 0

Therefore ,

3x - ( a+ b ) = 0 or 3x - ( a - b ) = 0

3x= ( a + b ) or 3x = ( a - b )

x = ( a + b ) / 3 or x = ( a - b ) / 3

I hope this helps you.

:)