Question

In Fig., a circle is inscribed in an equilateral triangle ABC of side 12 cm. Find the radius of the inscribed circle and the area of the shaded region. [Use π = 3.14 and 3 = 1.732]

Answer 1

Given that ABC is an equilateral triangle of side 12 cm. 
Construction:Join O and A, O and B, and O and C.
P, Q, R are the points on BC, CA and AB respectively then,
OP⊥BC
OQ⊥AC
OR⊥AB
Assume the radius of the circle as r cm.

Area of ∆AOB + Area of ∆BOC + Area of ∆AOC = Area of ∆ABC
⇒( 1/2× AB × OR) + (1/2× BC × OP) + (1/2× AC × OQ) = √3/4× (side)2.
⇒ (1/2× 12 × r) + (1/2× 12 × r) + (1/2× 12 × r) = √3/4× (12)2
⇒ 3 × 1/2× 12 × r = √3/4× 12 × 12
⇒ r = 2√3 = 2 × 1.73 = 3.46
Hence, the radius of the inscribed circle is 3.46 cm.

Area of the shaded region = Area of ∆ABC − Area of the inscribed circle
= [√3/4×(12)2 − π(2√3)2]
= [36√3 − 12π] 
= [36 × 1.73 − 12 × 3.14] 
= [62.28 − 37.68] 
= 24.6 cm2
∴ The area of the shaded region is 24.6 cm2

Answer 2

Answer:

Step-by-step explanation:

Pls view the attachment