In fig.a tent is in the shape of a cylinder surmounted by a conical top of same diameter. If the height and the diameter of a cylindrical part are 2.1 M and 3m and slant height of conical part is 2.8 M .find the cost of Canvas needed to make the tent if the Canvas is available at the rate of ₹ 500 per square metre.
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[FIGURE IS IN THE ATTACHMENT]
SOLUTION;
Given:
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 3 m
Radius of the cylindrical part = 3/2 m
Slant height (l) of conical part = 2.8 m
Total canvas used = CSA of conical part + CSA of cylindrical part
= πrl + 2πrh
= πr(2h+l)
= (22/7)×3/2(2×2.1+2.8)
= (22/7)×3/2(4.2+2.8)
= (22/7)×3/2(7)
= 11×3
= 33 m²
Cost of 1 m² canvas = ₹ 500
Cost of 44 m² canvas = 33 × 500 = 16500
The cost of Canvas needed to make the tent= ₹ 16500
Hence, it will cost ₹ 16500 for making such a tent.
HOPE THIS WILL HELP YOU...
SOLUTION;
Given:
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 3 m
Radius of the cylindrical part = 3/2 m
Slant height (l) of conical part = 2.8 m
Total canvas used = CSA of conical part + CSA of cylindrical part
= πrl + 2πrh
= πr(2h+l)
= (22/7)×3/2(2×2.1+2.8)
= (22/7)×3/2(4.2+2.8)
= (22/7)×3/2(7)
= 11×3
= 33 m²
Cost of 1 m² canvas = ₹ 500
Cost of 44 m² canvas = 33 × 500 = 16500
The cost of Canvas needed to make the tent= ₹ 16500
Hence, it will cost ₹ 16500 for making such a tent.
HOPE THIS WILL HELP YOU...
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