in fig AB parallel to CD find the value of angle FCE ? explain
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AB║CD GIVEN ∠ BAF=80∠ FEC=45AB║CD and line Eis extended to beyond A∠ BAF =∠ DFA =180 CORRESPONDING ANGLE80+∠DFA=180∠DFA=100 ∠DFA=∠EFC 100=∠EFG∠ FEC+∠EFG+∠FCE=180 sum of the Δis 18045+100+∠FCE=180145+∠FCE=180 ∠FCE=180-145∠FCE=35
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