In fig. ABC is a A in which AB = AC and AD is an altitude on BC. Prove that AD bisects LA
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proof- angle BAD= angle CAD
given - BDA=CDA = 90 ( AD altitude)
AB=AC (isosceles triangle)
therefore angle B=angle C
consider triangle ABD and CAD
angleB=angleC (A)
angleBDA = angleCDA. (A)
AD = AD (S)
By AAS property ABD congruent to ACD
by cpct BAD=CAD
hence proved
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