In fig. ABCD is a cyclic quadrilateral. If angle BAC=50° AND ANGLE DBC=60°, THEN FIND ANGLE BCD
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As ABCD is a cyclic quadrilateral
then in cyclic quadrilateral
sum of opp.angles is equal to 180 degree
angle bac +angle bcd =180
50 + angle bcd =180
angle bcd = 130
then in cyclic quadrilateral
sum of opp.angles is equal to 180 degree
angle bac +angle bcd =180
50 + angle bcd =180
angle bcd = 130
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