In fig ABCD is a parallelogram AE perpendicular DC and CF perpendicular AD if AB = 16 cm AE =8 cm and CF=10cm find AD
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CD = 16cm
Area of ||gm = b*h
= AE*CD
= 8*16
= 128cm^2. (1)
Also, area of ||gm = b*h
= CF*AD
= (10*AD)cm^2. (2)
From (1) and (2),
128cm^2 = (10*AD)cm^2
AD = 128/10
AD = 12.8cm.
Answered by
0
length of AD=12.8 cm
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