in fig.ABCD is a rectangle with sides AB=10cm and AD=5cm.find the area of EFG
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Anonymous:
guys,this is in R.D.Sharma-class 9th-pg:15.55
the answer is 50
no,25cm^@
*cm^2
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Answered by
13
we know that if a triangle and a parellelogram are on the same base and between the same parallel lines then the area of the triangle is half of the area of the parallelogram.
rectangle ABCD and triangle GEF are on the same base and between the same parallel lines.
area of GEF = half of area of rectangle ABCD
=1/2 AD CD
= 1/2 10*5
= 25cm^2
rectangle ABCD and triangle GEF are on the same base and between the same parallel lines.
area of GEF = half of area of rectangle ABCD
=1/2 AD CD
= 1/2 10*5
= 25cm^2
abcd has the base dc and gef has fe
they are because a rectangle is also a parallelogram
s,rectangle is,but check the fig.
no same base
GEF and ACD are congruent triangles. so we can consider any one of these two to calculate the area.
oh,thanks!
but,how come dc=fe?
ok,got it,srry
:)
:)
Answered by
9
area of EFG = half of area of rectangle ABCD
=1/2 AD* CD
= 1/2 10*5
= 25cm^2
=1/2 AD* CD
= 1/2 10*5
= 25cm^2
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