Question

In fig ABCD is parallelogram and P is mid point of AB.If ar(APCD)=36cm^2,then ar(triangle ABC)=

Answer 1

Answer:

ar △ABC= hx = 24$cm^{2}$

Step-by-step explanation:

From the above question,

In fig ABCD is parallelogram and P is mid point of AB.

Here, (APCD)=36cm square.

Let ABCD is aparellogram in which,

             AB=CD=2x

Then AP = PB = x.

This is because P is mid point.

A parallelogram is a two-dimensional geometrical shape whose sides are parallel to each other. It is a type of polygon having four sides (also called quadrilateral), where the pair of parallel sides are equal in length. The Sum of adjacent angles of a parallelogram is equal to 180 degrees.

Draw DE ⊥ AB = h

or  APCD = 36$cm^{2}$

                =  $\frac{1}{2}$ (x+2x)h

                = 36

ar △ABC  = $\frac{1}{2}$ h × 2x = hx

$\frac{1}{2}$ × 3x × h = 36

                = hx

                =24 (By executing from the above equation).

Hence, ar △ABC= hx = 24$cm^{2}$

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