in fig AC||BD and CE||DF if OA=12cm,AB=9cm,OC=8cm and EF=4.5cm find OE
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From the given information we get, (AB/AP) = (AC/AQ)
In triangle ABC, (AB/AP) = (AC/AQ)
By using converse of “Thales theorem” PQ is parallel to BC.
RD = x
In triangle ABD, PR is parallel to BD
AD = AR + RD
AD = 4.5 + x
(AB/AP) = (AD/AR)
(5/3) = (4.5 + x)/4.5
(5 x 4.5)/3 = 4.5 + x
7.5 = 4.5 + x
x = 7.5 – 4.5
x = 3
Here we need to find the length of AD = 4.5+x =4.5+3=7.5cm
In triangle ABC, (AB/AP) = (AC/AQ)
By using converse of “Thales theorem” PQ is parallel to BC.
RD = x
In triangle ABD, PR is parallel to BD
AD = AR + RD
AD = 4.5 + x
(AB/AP) = (AD/AR)
(5/3) = (4.5 + x)/4.5
(5 x 4.5)/3 = 4.5 + x
7.5 = 4.5 + x
x = 7.5 – 4.5
x = 3
Here we need to find the length of AD = 4.5+x =4.5+3=7.5cm
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