Question

In fig.AF is parallel to BD and AF is a bisector of angle EAC. if angle EAC=70°
Find angle ABC and angle ACD.​

Answer 1

Answer:

abc=60°

acd=110°

hope it will help you

mark me as brainlist

Answer 2

EAC is bisected byAF,

EAF =CAF=35

ACD= 180-CAF (int. angles on same side of transversal)

=180-35=145

ACB= 35 (alternate angles)

ABC + ACD =70 (ext. angle property)

ABC + 35 = 70

ABC = 70-35 = 35

or ABC = 35 ( corresponding to CAF)

answer=ABC=35 ; ACD= 145

hope it helps!