Question

In fig. AF is parallel to BD and AF is a bisector of the Angle EAC . If EAC=70 find the measure of angle ABC and angle ACD.​

Answer 1

ANSWER ACD = 145°; ABC= 35°

Step-by-step explanation:

AF//CD and AC transversal,

angleFAC+angleDCA=180° {co interior angles are supplementry}

angle EAF+angleFAC =70° {Given}

angle FAC=70/2 {FAC=EAF }

FAC=35°

35°+DCA=180°

DCA=145°

________________________________________

Angle EAF+FAC+CAB = 180°{angles on a st. line}

CAB=180°-70° =110°

CAB + ABC = ACD {Ext. angle property}

ABC=145°-110°

ABC = 35°

_________________________________________

Hopes it is correct and helps you