In fig. AP and Bg are perpendiculars to the line sequent
AB. prove that of the med part of line Segments. As and Po.
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Step-by-step explanation:
In △OAP and △OBQ,
AP=BQ(given)
∠OAP=∠OBQ=90
∘
∠OAP=∠OBQ(vertically opposite angles)
∴△OAP is congruent to △OBQ by AAS axiom
∴OA=OB by C.P.C.T.
and OP=OQ by C.P.C.T
⇒O is the midpoint of line segments AB and PQ
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