Question

in fig BA || ED and BC || EF
show that angle ABC = angle DEF​

Answer 1

produce DE to BC at point P

AB ll DP and BC is transversal

therefore,

<ABC = <DPC (corresponding angle )

now,

BC ll EF and DP is transversal

so,

<DEF= < DPC

therfore,

DEF=DPC=ABC

So,

ABC =DPC

Answer 2

Step-by-step explanation:

∆ABC =∆DEF

BA=ED ( parallel)

BC = Ef ( parallel)

∆Abc =∆DEF ( cpct )