In fig. Circle with centre D touches to ZACB at point A & B. If ZACB = 52° then Find ADB.
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Answer:
A = B = 90°
Given ACB = 52°
Now
ACB + A + B + ADB = 360°
52° + 90° + 90° + ADB = 360°
ADB + 232° = 360°
ADB = 360° - 232° = 128°
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