In fig., D is any point on the base BC produced of an isosceles triangle ABC. Prove that AD > AB.
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Answer:
AD > AB
Step-by-step explanation:
ΔABC is isoscelles
AB = AC
if we draw ⊥ AP from A at BC
then AP will bisect BC
BP = CP = BC/2
AB² = BP² + AP²
AD² = AP² + DP²
=> AD² = AP² + (CP + CD)²
=> AD² = AP² + (BP + CD)²
=> AD² = AP² + BP² + CD² + 2BPCD
=> AD² = AB² + CD² + 2BPCD
=> AD² > AB²
=> AD > AB
QED
Proved
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