In fig DE//BC, FIND X
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Since DE //BC
So, by Thales theorem, we have
AD/DB=AE/EC
x/x+1 =x+3/ x+5
x( x+5) = (x+1) (x+3)
x^2 + 5x = x^2 + 3x + x +3
5x - 3x- x = 3
x = 3
So, the value of x is 3.
So, by Thales theorem, we have
AD/DB=AE/EC
x/x+1 =x+3/ x+5
x( x+5) = (x+1) (x+3)
x^2 + 5x = x^2 + 3x + x +3
5x - 3x- x = 3
x = 3
So, the value of x is 3.
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