In Fig. (i), the man walks 2 m carrying a mass of 15 kg on his hand. In Fig. (ii), he walks the same distance
pulling the rope behind him. The rope goes over a pulley, and a mass of 15 kg hangs at its other end
in which case is the work done by gravity is greater ?
15 kgf
15 kg
Answers
case (i) : force applied on 15 kg mass , F = mg = 15kg × 9.8 m/s² = 147 N [ vertically downward ]
displacement of mass , s = 2m [ horizontally west direction ]
so, angle between force and displacement vector, Φ = 90°
we know,
work done = F.scosΦ
= 147 × 2 × cos90° = 0
case (ii) : force applied on mass, F = tension in rope = weight of body = mg
= 147 N [ horizontally west direction ]
displacement , s = 2m [ horizontally west direction ]
so, angle between F and s , Φ = 0°
so, work done = F.scosΦ
= 147 × 2 × 1 = 294 J
hence, in case (ii), more work is done.
Explanation:
work done in second case is greater
in case 1 displacement horizontal and force downward(mg)
thus @= 90°
work done= 0
in case 2 displacement and force horizontal
in same direction
thus @ = 0°
work done not equal to zero