in fig. if angle dab is equal to 60 degree and angle abd is equal to 50 degree then find angle acb
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Answer:
△ABD, ∠ABD + ∠ADB + ∠DAB = 180° [angle sum property of triangle]
50° + ∠ADB + 60° = 180°
⇒ ∠ADB = 70°
Now, ∠ACB = ∠ABD = 70° [∵ angle in same segment]
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Answer:
In∆ADB
Angle A+Angle B+Angle D=180⁰(sum of angles of∆ is equal to 180⁰)
60⁰+50⁰+ angle D=180⁰
110+angle D=180
Angle D=180-110
Angle D=70⁰
Angle D=angle C (angle in same segment)
so angle ACB=70⁰
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