Question

in fig if area of the parellelogram ABCD is 80cm^2 , the what is the area of triangle ADP?

Answer 1

Hii!!!

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Construct a line XP parallel to AB or CD.

=) XPBA and XPCD are llgms.

In a parallelogram XPBA :

Diagonal AP divides parallelogram into two equal part.

=) Area of Triangle XPA = 1/2 * Area of llgm XPBA..... Eq. 1.

In a parallelogram XPCD :

Diagonal DP divides parallelogram into two equal part.

=) Area of Triangle XPD = 1/2 * Area of a llgm XPCD..... Eq. 2.

Add eq 1 and 2..

=) Area of Triangle XPA + Area of Triangle XPD = 1/2* Area of llgm XPBA + 1/2 * Area of llgm XPCD

=) Area of Triangle APD = 1/2 (Area of llgm XPBA + Area of llgm XPCD)

=) Area of Triangle APD = 1/2 * Area of a llgm ABCD

=) Area of Triangle APD = 1/2 * 80 cm^2

=) Area of Triangle APD = 40 cm^2.

Hope it's helpful to u.