In Fig., if TP and TQ are two tangents to a circle with centre O so that POQ = 110°, then
find PTQ
Answers
Answered by
53
Answer:
70°
Step-by-step explanation:
L POQ = 110°(Given)
L OPT = 90°(By Radius Tangent Theorem)
L OQT = 90°(By Radius Tangent Theorem)
In quadrilateral POQT (By Angle Sum Property)
L POQ + L OPT + L OQT + L PTQ = 360°
110° + 90°+ 90°+ L PTQ = 360°
290° + L PTQ = 360°
L PTQ = 360° - 290°
L PTQ = 70°
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Answer:
L PTQ = 70°
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