in fig. Line AB and CD intersect at O. If ZAOC +
Z BOE =70° and Z BOD =40°, Find COE.
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★ Given
PQRS is a parallelogram( opp sides are equal )
⋆ PSQ = 32
⋆ SPQ =115
★ To Find
⋆ The value of x
Solution
PSQ = SQR = 32⁰ ( Alternate interior angle )
SPQ = SRQ = 115⁰( Opp angles of 11gm are equal)
In ∆SRQ
S + R + Q = 180⁰. ( Angle sum property)
x + 32⁰ + 115⁰ = 180⁰
x + 147⁰ = 180⁰
x = 180⁰ - 147⁰
x = 33°
Hope it helps u mate
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angle COD is a straight line =180
angle COD +bod +coa =180
180-110=angle coe
70=angle COE
IT is correct answer
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