In fig.<QPR=90°, segPM perpendicular seg QR and Q-M-R. PM=10,QM=8 , find QR.
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Answered by
8
Answer:
Step-by-step explanation:
QR=√(PM²+QM²)
= √100+64
= √164
= 12.8 (approx)
Answered by
4
Happy Promise Day Friends
∠PQM be θ∠PRM be 90-θtanθ=108,cotθ=810tan90-θ=10RM
cotθ=10
RM810=10RM
RM=1008
QR=8+1008=1648
Regards
∠PQM be θ∠PRM be 90-θtanθ=108,cotθ=810tan90-θ=10RM
cotθ=10
RM810=10RM
RM=1008
QR=8+1008=1648
Regards
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