Question

in fig o is centers of the circle. if angle d = 130 find angle cab

Answer 1

angle ACB=90 DEGREE
by theorem

(sum of opposite angles of quadrilateral = 180 degree)
hence
ANGLE ABC=180-130=50 DEGREE

(SUM OF ALL ANGLES OF TRIANGLE=180 DEGREE)

HENCE ,
ANGLE CAB=180 -(90+50)
=40 DEGREE
answer = 40 degree