Question

In fig. OA=OB and OD=OC show that tri.AOD=~∆BOC and AD||BC​

Answer 1

In ∆OAD and ∆OBC

OA=OB {given}
OD = OC { given }
angle AOD = angle BOC { vertically oppositie angles }
∆AOD=~∆BOC { SAS }

angle OBC = angle OAD {C.P.C.T.}


for that ADllBC


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