Question

In fig., P, Q and R are points on a circle with centre ‘O’. If PQR = 120°, then QPR
is equal to?

(a)10°
(c) 20°
15°
(d) 30°​

Answer 1

Answer:

30°

Step-by-step explanation:

PQR=POR

POR=120°

By angle sum property=360°

POR+PQR+ORQ+OPQ=360°

120°+120+x+x=360°

240°+2x=360°

2x=360°-240°

x=120°\2

x=60°

ORQ=60°

OPQ=60°

P+Q+R=180°

x+120+x=180°

2x=180°-120°

x=60°/2

x=30°