in fig , pq and pr are tangents draw from p if < qsr =40°, then <qpr is
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Answer:
In quadrilateral PQOR, ∠P+∠PQO+∠PRO+∠QOR=360∘
But ∠PQO=∠PRO=90∘ (Tangent is perpendicular to radius at point of contact)
Thus, 50∘+90∘+90∘+∠QOR=360∘
So, ∠QOR=130∘
In triangle OQR, ∠OQR+∠ORQ+∠QOR=180∘
Hence, 2.∠OQR+∠QOR=180∘
(because, ∠OQR=∠ORQ; (since OQ=OR, radii ))
Thus, 2.∠OQR+130∘=∠180∘
So, ∠OQR=25∘
Therefore option A is the answer
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