Question

In fig PQ is a chord of
length 8cm of a circle
of radius 5 cm. The tangents at P and Q
intersect at a point T . find the lengths of TP and TQ
plz answer fast​

Answer 1

Construction - Perpendicular from O on PQ and extend till T(OX)

perpendicular from centre bisects the chord

PX=QX=4 CM

Triangle POX

cos angle opx = px/op

=4/5

angle=37

Angle TPX =90-37=54

Cos tpx = px/tp

tp=px/cos 54

=4/3/5

=20/3

Sorry I cannot send a diagram right now.

please follow the steps exactly

Answer 2

Answer:

The, length of both the tangents TP & TQ =

$\huge \: = \frac{20}{3} cm$

for detailed explanation check the attachment,,

hope it's helpful!

:-)

Step-by-step explanation:

${ \colorbox{yellow}{\huge{\textbf{\textsf{{\color{red}{@}}{\red{❣}}{|}}}} \huge{\textbf{\textsf{{\color{navy}{O}}{\purple {P}} {\pink{BO}}{\color{pink}{Y࿐}}}}}}}$