Question

In fig seg PS is median of triangle of POR and PT is perpendicular to QR. prove that 1)
${pr}^{2} = {ps}^{2} + qr \times st + { \binom{qr}{2} }^{2}$
2)
${pq}^{2} = {ps}^{2} - qr \times st + { \binom{qr}{2} }^{2}$

Answer 1

In the attachment I have proved this problem.

To prove the results , Pythagoras theorem is applied to the triangles
PTR and PTQ.

Simplifications and modifications are done step by step to arrive the given
results.

I hope this answer help you