Question

IN Fig shown a sector OAP of a circle with centre O , containing angletetha. Ab is perpendicular to the radiouus OA and meets Op produced at B. Prove that the perimeter of shaded region is r (tantetha + sectetha + pitetetha/180 - 1 )

Experts this is tomoroow's board question...many of the children even toppers had left this...i want the solution plsss tomorrow will be my exam of maths...pls answer immediately

Answer 1

I can give you a hint for this question because i am in class 10 but i think it will work
Perimeter of shaded region
=AB+PB+AP
=r[tan theta+ sec theta + pietheta/180]
$r( \tan \alpha + \sec \alpha + \pi \alpha \div 180)$