In fig.,the sides BC,AB and CA of ΔABC are produced to points X,Y and Z respectively.If ACX=105° and YAZ=45°,find all angles of ΔABC
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angle BAC =45DEGREE (VERTICAL OPPOSITE ANGLES ARE EQUAL)
ANGLE BAC +ANGLE CBA = 105 (EXTERIOR ANGLE SUM PROPERTY)
LET ANGLE CBA = X
X+45 =105
105-45=60
ANGLE (BAC+CBA+BCA)=180
45+60+ANGLE BCA =180
BCA =180-(45+60)
BCA =180-105=75
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