In fig, two line segments AC and BD intersect each other at the point P such that PA = 6 cm, PB = 3 cm,
PC = 2.5 cm, PD = 5 cm, ∠APB = 40° arid ∠CDP = 30°. Then ∠PBA is equal to
(a) 110o
(b) 60°
(c) 50° (d) 30°
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Answered by
1
angle PBA is 110°
Step-by-step explanation:
As triangle PCD and PBA are similar triangles therefore angel PBA equals to 110°
Answered by
0
Answer:
PBA is equal to (a) 110^o
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