Question

In fig5, AB =PQ, ∠A =∠P and ∠ACD = ∠PRS. Prove that ∆ABC  ∆PQR.

Answer 1

see picture for amswer

Answer 2

Answer:

From the figure,

∠P=∠P (common angle for both triangles)

∠PQR=∠PRS [from the question]

So, △PQR∼△PRS

Then, PQ/PR=PR/PS=QR/SR

Consider PQ/PR=PR/PS

PQ/8=8/4

PQ=(8×8)/4

PQ=64/4

PQ=16cm.