Question

In Figure 1, a tower AB is 20 m high and BC, its shadow on the ground, is 20 3 m long. Find the Sun’s altitude.

Answer 1

if this is route 3 then the answer is 60 degree

Answer 2

suns altitude = route of (20)^2 + (20 3)^2
=route of 400+1200
=route of 1600
= 400 m
and
angel is
tan¤=20/20route3
=1/route3
¤=30degree