In figure 1 triangle abc is circumscribing a circle find the length of bc
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RA=AQ=4cm
RB=BP=3cm
AC=AQ+QC -> 11cm=4cm+QC
QC=7cm=PC
BP+PC=BC
3cm+7cm=10cm=BC
RB=BP=3cm
AC=AQ+QC -> 11cm=4cm+QC
QC=7cm=PC
BP+PC=BC
3cm+7cm=10cm=BC
Answered by
2
Answer:
Given, AR=4 cm
and, AR=AQ=4 (Tangents from the same point are equal)
CQ=AC−AQ=11−4=7 cm
CQ=CP=7 cm (Tangents from the same point are equal)
BR=BP=3 cm (Tangents from the same point are equal)
Now, BC=CP+BP
BC=7+3=10 cm
Step-by-step explanation:
- hope this helps you
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