Question

in figure 10, PR perpendicular RT and <P:<Q:<R = 3:2:1. find the <TRS. ​

Answer 1

Answer

P:Q:R = 3:2:1

Let Angles = 3x, 2x, x

P + Q + R = 180° (Angle Sum Property of a triangle)

=> 3x + 2x + x = 180

=> 6x = 180

=> x = 30°

P = 90°

Q = 60°

R = 30°

/_TRS = 180° - (/_TRP + /_PRQ) [Linear Pair]

=> /_TRS = 180 - 30 - 90

=> /_TRS = 60°

Answer 2

Answer:

<TRS = 60°

Step-by-step explanation:

Let the angel be x.

So, 3x , 2x , x

than,

P + Q + R = 180° ( by angle sum property )

then,

3x + 2x + x = 180°

6x = 180°

x = 180\6

x = 30°

3x = 3 × 30° , 2x = 2 × 20° , x = 30°

= 90° = 60°

Now,

30 + 90 + < TRS = 180° ( linear pair)

< TRS = 180 - 120

< TRS = 60°

So, answer is 60°

thank you!