the traffic lights at three different road crossings change after every 48 seconds 72 seconds and 108 seconds respectively if the changes simultaneously at 7 a.m. at what time will be the change simultaneously again
Answers
Step-by-step explanation:
first simultaneously at 7:00am
change =7:00am +48seconds
=7hours 48 sec (first crossing)
first simultaneously at 7:00am
change=7:00am+72 seconds
=7 hours+1 minute 12 seconds
=7 hours 1 minute 12 seconds (2nd crossing)
first simultaneously at 7:00am
change=7:00am +108 sec
=7 hours+1minute 48seconds
=7 hours 1 minute 48seconds(3rd crossing)
If the traffic lights change simultaneously at 8 a.m, then they will change simultaneously again after the LCM of the duration i.e. 48 s, 72 s and 108 s.
LCM of these durations by prime factorisation,,
- 48 = 2 × 2 × 2 × 2 × 3 = 2⁴ × 3
- 72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²
- 108 = 2 × 2 × 3 × 3 × 3 = 2² × 3³
LCM of 48, 72 and 108 is 2⁴ × 3³ = 432 seconds.
Hence, They will change after 432 seconds i.e. 7 minutes 12 seconds.
The traffic lights will change after:
- 8 am + 7 minutes 12 seconds
- 08 : 07 : 12 am