Question

in figure 10 , PR RT and angle P :Q:R=3:2:1. find the value of aangleTRS.

Answer 1

Step-by-step explanation:

let 3x,2x and x be the angles of PQR respectively

in triangle ∆ PQR

We have 3x+2x+x = 180°

6x = 180°

x = 180°/6 = 30°

therefore L P=3x= 3 × 30 = 90°

L Q = 2x= 2 × 30° = 60°

and L R = x= 30°

we know that, L TRS + L TRP + L PRQ = 180°

L TRS + 90° + 30° = 180°

L TRS = 180°-120° = 60°