Question

in figure 11.35,ABCDE is a regular pentagon .If angle EBD =36 degree ,find angle 1,2&3

Answer 1

we know that sum of angles A , B,C,D and E = 540 degree
there fore each angle A , B,C ,D and E measures = 108 degree
Angle A = 108 degree
now in triangle ABE ,
AB=AE ( because it is regular pentagon, all sides are equal)
so Triangle ABE is isosceles triangle.
Angle ABE = angle AEB                            (i)
now angle A + angle AEB+ angle AEB = 180
104 + 2 angle ABE= 180  (because of (i) )
angle AEB =36 degree (which is angle 2)
similarly angle 3 = 36 degree

Answer 2

hope this is helpful for you...................