Question

In figure 11.36 ABCD is a trapezium x = 4/3Y , Y = 3/8z then find the Value of x . ​

Answer 1

Answer:

Here's Your correct answer

Step-by-step explanation:

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Answer 2

Answer:

your answer :

Given that

x = 4/3 Y

&

Y = 3/8 z or z = 8/3 Y

ABCD is a trapezium

& AB || CD

: . ∆B + ∆C = 180° ( co interior angles )

∆X + ∆Y + ∆Z = 180°

4/3Y + Y + 8/3Y = 180°

$\frac{4y \: + 3y \: + 8y \: }{3} = 180° \: \\ \\ \frac{15y}{3 } = 180° \:$

5Y = 180°

Y = 180/5

Y = 36

X = 4/3 Y

$\: X = \: \frac{4}{3} \times 36$

X = 4 × 12

X = 48° Answer

Step-by-step explanation:

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