Question

In Figure 11, two lines AB and CD intersect at o such that ZBOC = 145º. Find the remaining
angles​

Answer 1

Answer:Answer:

35°, 35° and 145°

Step-by-step explanation:

The angle opposite BOC will be 145 following the opposite angle theorem. 145+145=290°. Now subtract 290 from 360(sum of all angles around a point is 360°) and you get 70. Since other 2 angles will be equal due to opposite angle theorem divide 70 by 2 and y out get two 35° angles

please put brainliest

Step-by-step explanation:

Answer 2

Step-by-step explanation:

In the fig:

<boc=145°

<aod=145°(vertically opposite angles)

<boc+<bod=180(supplementary angles)

145°+<bod=180

<bod=180-145

<bod=75°

<bod= <coa=75°(vertically opposite angles)