In Figure 16.3, find the area of the quadrilateral RIJH, where Al 1 RJ, HT I RJ, RJ = 24 cm, and AI= 7.5 cm,
HT= 12 cm.
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Answer:
area = 1/2 * d1*d2
d1 =7. 5 cm
d2 = 12 cm
area = 1/2*7.5*12
=7.5*6
45 cm^2
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